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post #1 of 13 (permalink) Old Mar 5th, 2006, 1:43 pm Thread Starter
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Forum Humor

Thought this was funny...

this is possibly an old one that someone else shared that I thought I'd pass along....

How many forum members does it take to change a light?

1 to change the light bulb and to post that the light bulb has been changed

14 to share similar experiences of changing light bulbs and how the light bulb could have been changed differently

7 to caution about the dangers of changing light bulbs

27 to point out spelling/grammar errors in posts about changing light bulbs

53 to flame the spell checkers

41 to correct spelling/grammar flames

6 to argue over whether it's "light" or "light bulb" ...

another 6 to condemn those 6 as anal-retentive

2 industry professionals to inform the group that the proper term is "lamp"

15 know-it-alls who claim *they* were in the industry, and that "light bulb" is perfectly correct

156 to email the participant's ISPs complaining that they are in violation of their "acceptable use policy"

109 to post that this group is not about light bulbs and to please take this discussion to a light group

203 to demand that cross posting to hardware forum, off-topic forum, and light group about changing light bulbs be stopped

111 to defend the posting to this group saying that we all use light bulbs and therefore the posts *are* relevant to this group

306 to debate which method of changing light bulbs is superior, where to buy the best light bulbs, what brand of light bulbs work best for this technique, and what brands are faulty

27 to post URL's where one can see examples of different light bulbs

14 to post that the URL's were posted incorrectly and then post the corrected URL's

3 to post about links they found from the URL's that are relevant to this group which makes light bulbs relevant to this group

33 to link all posts to date, quote them in their entirety including all headers and signatures, and add "Me too"

12 to post to the group that they will no longer post because they cannot handle the light bulb controversy

19 to quote the "Me too's" to say "Me three"

4 to suggest that posters request the light bulb FAQ

44 to ask what is a "FAQ"

4 to say "didn't we go through this already a short time ago?"

143 to say "do a Google search on light bulbs before posting questions about light bulbs"

1 forum lurker to respond to the original post 6 months from now and start it all over again...

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post #2 of 13 (permalink) Old Mar 5th, 2006, 7:45 pm
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Seems about right

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post #3 of 13 (permalink) Old Mar 8th, 2006, 4:23 am
 
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post #4 of 13 (permalink) Old Apr 13th, 2006, 6:00 pm
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Cool

um..., it's not a "light bulb", it's a lamp.
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post #5 of 13 (permalink) Old Apr 13th, 2006, 10:07 pm
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Quote:
Originally Posted by Warp9
um..., it's not a "light bulb", it's a lamp.
Now, don't you start!!

Bob.
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post #6 of 13 (permalink) Old Apr 13th, 2006, 10:41 pm
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post #7 of 13 (permalink) Old Apr 13th, 2006, 11:29 pm
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Cool LAMP : What the un-initiated call a light bulb.

"LAMP : What the un-initiated call a light bulb."

"The bulb is the decorative glass or plastic housing that diffuses the light distibution."

from;
http://www.asu.edu/hc/electrics/Ligh...ing_terms.html

And for good measure;

LUMINOUS INTENSITY AND FLUX:
The unit of luminous intensity I is the candela (cd) also known as the international candle. The intensity of a light source is commonly referred to as its candlepower.

The unit of luminous flux F is the lumen (lm). One lumen is equal to the luminous flux which falls on each square meter (m2) of a sphere one meter (1m) in radius when a 1-candela isotropic light source (one that radiates equally in all directions) is at the center of the sphere. Since the area of a sphere of radius r is 4pr2, a sphere whose radius is 1m has 4pm2 of area, and the total luminous flux emitted by a 1-cd source is therefore 4p1m.

Thus the luminous flux emitted by an isotropic light source of intensity I is given by:

F = 4pI where

Luminous flux (lm) = 4p luminous intensity (cd)

ILLUMINATION:

The illumination (or illuminance) E of a surface is the luminous flux per unit area that reaches the surface:

E = F/A Illumination = luminous flux / area

Luminous Intensity & Luminous Flux:

lumens = 4π cd cd = lumens


lumens = 4π (Mean Spherical Candlepower)

fc = cd cd = fc d
d

lumens = fc 4π d fc = lumens
4π d


Illumination:
Inverse Square Law: E = I
d Cosine Law: E = I cos θ
where θ is angle of incidence d d

Related Formulas

10.764 fc = lux
1 lux = 0.0929 fc

10.764 lumens / sq. ft = lux

lumens / m = lux
1 cd / sq. ft. = π fL (foot-Lambert)

3.426 fL = nits = cd / m


1 fL = 1 lumen / sq. ft.
1 fL = 3.426 cd / m

1 cd = 1 lumen per steradian (unit solid angle), where steradian unit solid angle is a cone. Unit solid angle is photometric brightness, where the spherical surface is:
S = 4π

If r = 1, then there are 4π lumens in the sphere, (12.566 lumens)


Source: Engineering Dept.

OK, OK, so the above has nothing to do with lamps, bulbs, or any combination of therin. But, it looked pretty offical like on the page I got it from.
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post #8 of 13 (permalink) Old Apr 14th, 2006, 1:04 am
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Quote:
Originally Posted by Warp9
"LAMP : What the un-initiated call a light bulb."

"The bulb is the decorative glass or plastic housing that diffuses the light distibution."

from;
http://www.asu.edu/hc/electrics/Ligh...ing_terms.html

And for good measure;

LUMINOUS INTENSITY AND FLUX:
The unit of luminous intensity I is the candela (cd) also known as the international candle. The intensity of a light source is commonly referred to as its candlepower.

The unit of luminous flux F is the lumen (lm). One lumen is equal to the luminous flux which falls on each square meter (m2) of a sphere one meter (1m) in radius when a 1-candela isotropic light source (one that radiates equally in all directions) is at the center of the sphere. Since the area of a sphere of radius r is 4pr2, a sphere whose radius is 1m has 4pm2 of area, and the total luminous flux emitted by a 1-cd source is therefore 4p1m.

Thus the luminous flux emitted by an isotropic light source of intensity I is given by:

F = 4pI where

Luminous flux (lm) = 4p luminous intensity (cd)

ILLUMINATION:

The illumination (or illuminance) E of a surface is the luminous flux per unit area that reaches the surface:

E = F/A Illumination = luminous flux / area

Luminous Intensity & Luminous Flux:

lumens = 4π cd cd = lumens


lumens = 4π (Mean Spherical Candlepower)

fc = cd cd = fc d
d

lumens = fc 4π d fc = lumens
4π d


Illumination:
Inverse Square Law: E = I
d Cosine Law: E = I cos θ
where θ is angle of incidence d d

Related Formulas

10.764 fc = lux
1 lux = 0.0929 fc

10.764 lumens / sq. ft = lux

lumens / m = lux
1 cd / sq. ft. = π fL (foot-Lambert)

3.426 fL = nits = cd / m


1 fL = 1 lumen / sq. ft.
1 fL = 3.426 cd / m

1 cd = 1 lumen per steradian (unit solid angle), where steradian unit solid angle is a cone. Unit solid angle is photometric brightness, where the spherical surface is:
S = 4π

If r = 1, then there are 4π lumens in the sphere, (12.566 lumens)


Source: Engineering Dept.

OK, OK, so the above has nothing to do with lamps, bulbs, or any combination of therin. But, it looked pretty offical like on the page I got it from.
hmmmm...lol...engineer? I'm impressed. or was 'til I read the last line!

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post #9 of 13 (permalink) Old Apr 15th, 2006, 7:35 pm
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post #10 of 13 (permalink) Old Aug 20th, 2007, 10:55 am
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must keep this thread going.

am only posting this to be in line with the original thread.
bulb= lamp= light= absent of darkness, etc...

turn on your light and so let your light shine.
ride safe...
God bless...

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